josiah51
josiah51
02-12-2017
Mathematics
contestada
Somebody solve this for me
Respuesta :
altavistard
altavistard
02-12-2017
The std. eqn. of a circle with center at (h,k) and radius r is:
(x-h)^2 + (y-k)^2 = r^2.
Here, (h,k) is (2, -4) and r is 3, so we get:
(x-2)^2 + (y-[-4])^2 = 3^2, or (x-2)^2 + (y+4)^2 = 3^2
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