Respuesta :

twvogels
[tex]f(g(x))=f(\sqrt{x-2})[/tex]
[tex]f(g(x))=3(\sqrt{x-2})^{2}+4[/tex]
[tex]f(g(x))=3(x-2)+4[/tex]
[tex]f(g(x))=3x-6+4[/tex]
[tex]f(g(x))=3x-2[/tex]

Domain:
g(x) must be greater than or equal to zero (no square roots of negative numbers) therefore x must be greater than or equal to 2.  Answer is B. 
jbmow
The second answer is correct.
Square g(x), multiply by 3, 3x-6+4 = 3x-2.
The domain depends on the square root term which must have its argument greater or equal to zero.
Therefore x-2 >= 0, so x>=2