First find the molar mass (mm) for Methane--> CH4 = 12+(1×4)
= 16 grams/mole CH4 --> now flip this:
So the = # of moles (n)
= 12.5g CH4 × 1 mole CH4 / 16g CH4
n = 0.78 moles
P = 1.30 atm, T = 40C = 273K + 40C
= 313K, V = ??
PV = nRT --> V = nRT/P
V = (0.78)(.082)(313) / 1.30
V = 20.1 / 1.30 = 15.4 L
