[tex] \frac{ V_{1} }{ T_{1} } [/tex] = [tex] \frac{ V_{2} }{ T_{2} } [/tex]
[tex] V_{1}[/tex] = 0.0521 L
[tex] T_{1}[/tex] = 293.15 K
[tex] T_{2}[/tex] = 366.65 K
Solve for [tex] V_{2} [/tex]
[tex] \frac{0.0521 L}{293.15 K} [/tex] = [tex] \frac { V_{2} }{366.65 K} [/tex]
[tex] V_{2} [/tex] = 0.06516 L or 65.2 mL
