Data:
pH = 5.2
[H+] = ?
Knowing that: (Equation to find the pH of a solution)
[tex]pH = -log[H+][/tex]
Solving:
[tex]pH = -log[H+][/tex]
[tex]5.2 = - log [H+][/tex]
Knowing that the exponential is the opposite operation of the logarithm, then we have:
[tex][H+] = 10^{-5.2}[/tex]
[tex]\boxed{\boxed{[H+] = 6.30*10^{-6}}}\end{array}}\qquad\quad\checkmark[/tex]
