Respuesta :

LammettHash
[tex]i^{233}=i^{232+1}=i^{232}i[/tex]

Since 232 is divisible by 4, and [tex]\dfrac{232}4=58[/tex], you have

[tex]i^{232}i=\left(i^4\right)^{58}i=1^{58}i=i[/tex]

Answer:

the corect awser would be c

Step-by-step explanation:

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