SOLUTION
From the graph
The slope of line A is
[tex]m=\frac{60-20}{2-0}=20[/tex]
The slope of line B is
[tex]n=\frac{80-60}{6-2}=5[/tex]
The slope of line C is
[tex]p=\frac{110-80}{9-6}=10[/tex]
The least segment is the segment with the least slope.
The required arrangement is
[tex]B,C,A[/tex]
