[tex]R(x)=\frac{x+6}{x(x+8)}[/tex]
We know that the graph has a horizontal asymptote y = 0 and we can also check that:
[tex]R(-6)=\frac{-6+6}{(-6)(-6+8)}=\frac{0}{-12}=0[/tex]
Therefore, the graph of R intersects the horizontal or oblique asymptote at (-6,0)
