Solution:
Given a right triangle;
Using the opposite side and the hypotenuse side;
[tex]\begin{gathered} \sin P=\frac{opposite}{hypotenuse} \\ \\ opposite=12,hypotenuse=13 \end{gathered}[/tex]
Thus;
[tex]\begin{gathered} \sin P=\frac{12}{13} \\ \\ P=\sin^{-1}(\frac{12}{13}) \\ \\ P=67.38^o \\ \\ P\approx67^o \end{gathered}[/tex]
CORRECT ANSWER:
[tex]67^o[/tex]
