Answer:
14.61g
Explanation:
A 1 M solution corresponds to 1 mole of the solute (here, sodium chloride, NaCl) in 1 L of solvent (here probably water). Since the question calls for only making 250 mL, or 1/4 of a L, only 1/4 or 0.25 mol will be required. The molecular weight of NaCl is 58.44 g/mol so you will need:
0.25 mol * 58.44 g/mol = 14.61 g
