Answer:
[tex]x=90^\circ,270^\circ[/tex]
Step-by-step explanation:
[tex]sinxcosx=-cosx[/tex]
[tex]sinxcosx+cosx=0[/tex]
[tex]cosx(sinx+1)=0[/tex]
[tex]cosx=0[/tex]
[tex]x=90,270[/tex]
[tex]sinx+1=0[/tex]
[tex]sinx=-1[/tex]
[tex]x=270[/tex]
Therefore, the angles that satisfy the equation are [tex]x=90^\circ,270^\circ[/tex]
