Answer:
Hey kimalonzo59!
· Calculate specific heat as c = Q / (mΔT). In our example, it will be equal to c = -63,000 J / (5 kg * -3 K) = 4,200 J/ (kg·K). This is the typical heat capacity of water.
I hope this Helps, Have an Awesome Day!
~ Chloe Marcus ❤
