Answer:
In this exercise we need to solve the equation
3(x-2) = 2x + 6 - 2
We operate the parentheses and the right side
3(x-2) = 2x + 4
3x - 6 = 2x + 4
We add 6 to both sides
3x -6 + 6 = 2x + 4 + 6
3x = 2x + 10
We substract 2x
3x - 2x = 2x + 10 - 2x
x = 10
