Answer:
A has greater volume.
Greater by [tex]43in^3[/tex]
Step-by-step explanation:
[tex]volume \ of \ can = \pi r^2 h[/tex]
[tex]r_A = 3 in, \ h_A = 6 in\\Volume_A = \pi \times 9 \times 6 = 169.65 = 170 in^3\\\\\\r_B = 2.25in , \ h_B = 8\\Volume_B = \pi \times 5.0625 \times 8 = 127.23 = 127in^3[/tex]
