Answer:
i dont now
Step-by-step explanation:
inde man kona ka balo sorry
quadrant 1 and quadrant IV
(a)
secθ > 0 in quadrants 1 and IV
sinθ > 0 in quadrants 1 and II
Thus θ is in quadrant I
(b)
cosθ > 0 in quadrants I and IV
cotθ < 0 in quadrants II and IV
Thus θ is in quadrant IV
