Respuesta :

Answer:

0.1389mol

Explanation:

no of mol of Al in 7.5g=7.5g/27gmol^-1

=75/270mol

according to tge chemical equation

2mol of Al:1 mol of Al2S3

1mol of Al:0.5mol of Al2S3

therefore 75/270 mol of Al : 0.5*75/270 mol of Al2S3

=0.1389mol