Answer:
The answer is D.
Step-by-step explanation:
You only have to substitute π value and r value into the formula :
[tex]s.a = 4\pi {r}^{2} [/tex]
[tex]let \: \pi = 3,r = 2[/tex]
[tex]s.a = 4 \times 3 \times {2}^{2} [/tex]
[tex]s.a = 12 \times 4[/tex]
[tex]s.a = 48 \: {m}^{2} [/tex]
