Answer:
C. 6
Step-by-step explanation:
If x-3 is a factor of the polynomial f(x)=3x^(3)-10x^(2)+x+k, then x = 3 is one of the zeros of the polynomial.
Let p(x) = 0 where x = 3
Substitute this values into the polynomial
0 =3(3)^(3)-10(3)^(2)+3+k
0 = 3^4-10(9)+3+k
0 = 81-90+3+k
0 = -9+3+k
0 = -6+k
k -6 = 0
k = 6
Hence the value of k is 6
