02-04-2020
Mathematics

contestada

in the right triangle shown, angle B = 60° and BC = 2sqrt3

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ssatrudhanyadav93 ssatrudhanyadav93

02-04-2020

Answer:

BC=2SQ.RT3

SIN 60=P/H

SQ RT.3/2=P/2SQ.RT3

P=1

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