10+(5v-7)=5v-3
pretend that there is a 1 in front of the bracket
10+1(5v-7)=5v-3
mutiply the bracket by 1
(1)(5v)= 5v
(1)(-7)= -7
10+5v-7= 5v-3
10-7+5v= 5v-3
3+5v=5v-3
move 5v to the left side
sign changes from +5v to -5v
3+5v-5v= 5v-5v-3
3+0= 0-3
3=-3
Answer:
no solution
