proutyhaylee
proutyhaylee proutyhaylee
  • 04-02-2019
  • Mathematics
contestada

Solve 2^x=32 and rewrite this equation in a logarithmic form

Respuesta :

wegnerkolmp2741o
wegnerkolmp2741o wegnerkolmp2741o
  • 04-02-2019

Answer:

x=5

x = log2(32)

Step-by-step explanation:

2^x=32

Rewrite 32 as 2^5

2^x = 2^5

Since the bases are the same, the exponents have to be the same

x=5

2^x=32

Take log base 2 on each side

log2(2^x) = log2(32)

x = log2(32)

Answer Link

Otras preguntas

Please help me understand how to do this! In ΔRST shown below, segment SU is an altitude: What property or definition is needed to prove that ΔRUS is similar to
plz help me with this
Find the distance between -422 and 166.
How does development differ from growth?
4 + 2/7x = 8 what does x equal
14 karat gold is a mixture of pure gold and other metals. One ounce of 14 karat gold weighs 0.58 ounce of pure gold. If a 14 karat gold necklace weighs 1.8 ounc
Which Prussian officer turned the disorderly Continental Army into a skilled fighting force?   A. Haym Salomon   B. Baron Friedrich von Steuben   C.
The two main sources of government revenue are
Two years of local Internet service costs $685, including the installation fee of $85. What is the monthly fee?
Explain why -4 is greater than -10 even though 4 is less than 10