[tex]f(x) = 10 + \frac{1}{2} {(4x - 8)}^{2} \\ \\ f(3) = 10 + \frac{1}{2} {(4 \times 3 - 8)}^{2} \\ \\ f(3) = 10 + \frac{1}{2} {(12 - 8)}^{2} \\ \\ f(3) = 10 + \frac{1}{2} {(4)}^{2} \\ \\ f(3) = 10 + \frac{1}{2} \times 16 \\ \\ f(3) = 10 + 8 \\ \\ \boxed{ \red{ \large{f(3) = 18}}}[/tex]
