primarydirecti
primarydirecti primarydirecti
  • 04-06-2018
  • Mathematics
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Solve sin θ = 0.95 for -90º ≤ θ ≤ 90º

Respuesta :

Professor1994 Professor1994
  • 05-06-2018
sin θ = 0.95
Solving for θ:
θ = sin^(-1) 0.95
θ = 71.80512766°
θ = 71.8°
The sine is positive in the interval 0° to 180°

Answer: θ = 71.8°
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